Question

Show that,
(tan 'theeta'+ sec 'theeta' - 1) /
( tan 'theeta' - sec 'theeta' +1)
= ( 1+sin 'theeta') / cos 'theeta'​

Answer 1

Answer:

hope that this will help you.

Answer 2

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➲ ʏᴏᴜʀ ǫᴜᴇsᴛɪᴏɴ:⍰

Show that,

Show that,(tan 'theeta'+ sec 'theeta' - 1) /

Show that,(tan 'theeta'+ sec 'theeta' - 1) /( tan 'theeta' - sec 'theeta' +1)

Show that,(tan 'theeta'+ sec 'theeta' - 1) /( tan 'theeta' - sec 'theeta' +1)= ( 1+sin 'theeta') / cos 'theeta'

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Here, i am holding the "THETAS" as "A".

So, we can proceed our solution as under :

L.H.S

(tan A + sec A - 1)/(tan A - sec A + 1)

= (tan A + sec A - sec²A + tan²A)/(tan A - sec A + 1)

= [tan A + sec A - {(sec A+tan A) (sec A - tan A)}]/[tan A - sec A + 1]

= [tan A + sec A (1 - sec A + tan A)]/(tan A - sec A + 1)

= tan A + sec A

= sin A/cos A + 1/cos A

= ( 1 + sin A ) / cos A

= R. H. S

==================================

ULTIMATELY,

L.H.S. = R.H.S. (PROVED)

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