Question

show that
tan18 tan16 tan42 tan74=1​

Answer 1

$\huge\mathbb{SOLUTION}$

To prove = tan18×tan16×tan42×tan74=1

Proof:-

LHS

=tan18×tan(90-18)×tan42×tan(90-42)

= tan18×cot18×tan42×cot42

= 1×1 = 1 = RHS proved

Note :-

tan∅×cot∅ = 1

Answer 2

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