Show that tan2 theta+ tan 4 theta = sec4 theta- sec2 theta ( theta = 90)
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2
Answer:
L.H.S.
tan
4
θ+tan
2
θ
tan
2
θ(1+tan
2
θ)
(sec
2
θ−1)(sec
2
θ) ∵tan
2
θ+1=sec
2
θ
sec
4
θ−sec
2
θ
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Answer:
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