Show that tan20º tan40º tan60º tan80º = 3
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Answer:
we know that tan♧°cot♧°=1
given L.H.S.
tan20°tan40°tan60°tan80°
=(3)^1/2{tan20°tan40°tan80°}
we know a formula
tan♧°tan(60-♧)°tan60+♧)°=tan3♧°
so we get ,
=(3)^1/2{tan60°}
=(3)^1/2×(3)^1/2
=3
hence proved
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