Question

Show that :
tan²A - tan²B = sin²A - sin²B
------------------
cos²A × cos²B

Please answer this question with full explanation (◍•ᴗ•◍)❤​

Answer 1

Step-by-step explanation:

gave any questions please

yen madatiri

Answer 2

Answer- The above question is from the chapter 'Introduction to Trigonometry'.

Trigonometry- The branch of Mathematics which helps in dealing with measure of three sides of a right-angled triangle is called Trigonometry.

Trigonometric Ratios:

sin θ  = Perpendicular/Hypotenuse

cos θ = Base/Hypotenuse

tan θ = Perpendicular/Base

cosec θ = Hypotenuse/Perpendicular

sec θ = Hypotenuse/Base

cot θ = Base/Perpendicular

Also, tan θ = sin θ/cos θ and cot θ = cos θ/sinθ

Trigonometric Identites:

1. sin²θ + cos²θ = 1

2. sec²θ - tan²θ = 1

3. cosec²θ - cot²θ = 1

Given question: Show that

$tan^{2}A - tan^{2}B = \dfrac{sin^{2}A \: - \: sin^{2}B}{cos^{2}A \times cos^{2}B}$

Solution:  (Solution in attachment.)