Question

show that tan2x.tan3x=tan3x-tan2x-tanx​

Answer 1

Answer:

∵tan3x=tan(2x+x)

⇒tan3x=

1−tan2x.tanx

tan2x+tanx

⇒tan3x−tan3xtan2xtanx=tan2x+tanx

⇒tan3x−tan2x−tanx=tan3xtan2xtanx

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