show that tan²x+tan⁴x=sec⁴x-sec²x
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Answer:
tan²x + tan⁴x = sec⁴x – sec²x
Step-by-step explanation:
LHS:
tan²x + tan⁴x
= (1 – sec²x) + tan⁴x
= 1 – sec²x + tan⁴x
= 1 + tan⁴x – sec²x
= (1 + tan⁴x) – sec²x
= sec⁴x – sec²x
hence, LHS=RHS (Proved).
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