Math, asked by Kir6tEsmnitispal, 1 year ago

show that tan3x-tan2x-tanx =tan3x*tan2x*tanx

Answers

Answered by ARoy
4
3x-2x=x
∴, tan(3x-2x)=tanx
or, (tan3x-tan2x)/(1+tan3x.tan2x)=tanx
or, tan3x-tan2x=tanx+tan3x.tan2x.tanx
or, tan3x-tan2x-tanx=tan3x.tan2x.tanx (Proved)
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