Question

Show that tan4 theta + tan 2 theta = sec 4 theta minus sec 2 theta​

Answer 1

See attachment for ans

Answer 2

Answer:

Step-by-step explanation:

take the LHS

$tan^{4}$∅+$tan^{2}$∅

$tan^{2}$∅(1+$tan^{2}$∅) .          ⇒ 1

we know that,

$1+tan^{2}$∅ = $sec^{2}$∅

therefore from 1

($sec^{2}$∅-1)$sec^{2}$∅

$sec^{4}$∅ - $sec^{2}$∅

thus LHS = RHS

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