Show that tan8A - tan5A - tan3A = tan8A tan5A tan3A.
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Answer:
Write tan8A = tan(5A+3A) i.e. (tan5A+tan3A)/(1-tan5Atan3A)
=(tan5A+tan3A)/(1-tan5Atan3A) - (tan5A + tan3A)
=(tan5A+tan3A)[1/(1-tan5Atan3A) - 1]
=(tan5A+tan3A)/(1-tan5Atan3A)[1-1+ tan5Atan3A]
=tan8Atan5Atan3A
so k=1.
i hope u understand
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