Question

show that (tanA sinA)+cosA= secA

Answer 1

Answer:

here is the solution of ur ques

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Answer 2

Take LHS
tanAsinA+cosA
sinA/cosA*sinA+cosA
sin*2A/cosA+cosA
sin*2A+cos*2A/cosA
1/cosA
secA
Therefore LHS=RHS