show that (tanA sinA)+cosA= secA
Answers
Answered by
15
Answer:
here is the solution of ur ques
i hope it will help u☺☺
Attachments:
Answered by
4
Take LHS
tanAsinA+cosA
sinA/cosA*sinA+cosA
sin*2A/cosA+cosA
sin*2A+cos*2A/cosA
1/cosA
secA
Therefore LHS=RHS
tanAsinA+cosA
sinA/cosA*sinA+cosA
sin*2A/cosA+cosA
sin*2A+cos*2A/cosA
1/cosA
secA
Therefore LHS=RHS
Similar questions