Show that tanA. sinA+cosA=secA
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Step-by-step explanation:
ANSWER
Consider LHS =tanAsinA+cosA
=
cosA
sinA
sinA+cosA (∵tanA=
cosA
sinA
)
=
cosA
sin
2
A
+cosA=
cosA
sin
2
A+cos
2
A
(But sin
2
A+cos
2
A=1)
=
cosA
1
=secA= RHS
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