Math, asked by mangeshparkhe999, 2 months ago

show that tanA.sinA+cosA=secA

Answers

Answered by shashankofficial

5

Answer:

tanA.sinA+cosA=secA

sinA/cosA.sinA+cosA

sin²A/cosA+cosA

(sin²A+cos²A)/cosA

1/cosA

secA

Step-by-step explanation:

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