Question

show that tanA + sinA/ tanA -sinA= sec +1/sec-1

Answer 1

Hi,

LHS = ( tanA + sinA ) / ( tanA - sinA )

= ( sinA/cosA + sinA/1)/(sinA/cosA -sinA/1)

[ since tanA = sinA /cosA ]

divide numerator and denominator with

sinA, we get

= ( 1/cosA + 1 )/( 1/cosA - 1 )

= ( secA + 1 ) / ( secA - 1 )

[ since 1/ cosA = sec A ]

= RHS

I hope this helps you.

:)

Answer 2

Kindly find attached file for solution