Question

show that
$1.2 ^{2} + 2.3 {}^{2} + ...... + n(n + 1) \div 1^{2} .2 +2 {}^{2}.3 + .... + n {}^{2} (n + 1) = 3n + 5 \div 3n + 1$

Answer 1

I don't think that ur question is complete.....

Answer 2

here is the answer hope ut helps