Question

show that
$1 - \tan}^{2} a \div 1 + \tan^{2} a = 2 \cos^{2} a - 1$
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

Given LHS

=1-tan^2a ÷ 1+tan^2a

=1-tan^2a÷sec^2a

( 1+tan^2a=sec^2a)

=1-(sec^2a-1) ÷sec^2a

(tan^2a=sec^2a-1)

=now, 1-sec^2a+1÷sec^2a

=2-sec^2a÷sec^2a

=2÷sec^2a-sec^2a÷sec^2a

=2cos^2a-1

(1÷sec^2a=cos^2a)

Hence proved