Question

Show that
$\sf(x - 1)$
is a factor of
$\sf {x}^{3} - {5x}^{2} - x + 5$
Hence, factorise
$\sf {x}^{3} - {5x}^{2} - x + 5$
Good answer with explanation needed.

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Answer 1

..QUESTION..

Show that :

( x - 1 ) is a factor of x³ - 5x² - x + 5

also factorise the equation .

..ANSWER..

Given ,

ㅤㅤㅤ➪ p(x) = x³ - 5x² - x + 5

ㅤㅤㅤ➪ g(x) = ( x - 1 )

☯︎ Zeroes of the g ( x ) is =

ㅤㅤㅤ➪ x - 1 = 0

ㅤㅤㅤ➪ x = 0 + 1

ㅤㅤㅤ➪ x = 1

•°• Putting the value :

➪ p(x) = x³ - 5x² - x + 5

➪ p( 1 ) = ( 1 )³ - 5 ( 1 )² - ( 1 ) + 5

ㅤ ㅤㅤ = 1 - 5 - 1 + 5

ㅤㅤㅤ = 1 - 1 - 5 + 5

ㅤㅤㅤ = 0

•°• ( x - 1 ) is the factor of x³ - 5x² - x + 5

★ Now ,

» Factorisation of x³ - 5x² - x + 5

ㅤ➪ x³ - 5x² - x + 5

ㅤ➪ x² ( x - 5 ) - 1 ( x - 5 )

ㅤ➪ ( x - 5 ) ( x² - 1 )

ㅤ➪ ( x - 5 ) ( x² - 1² )

ㅤ➪ ( x - 5 ) {( x + 1 )( x - 1 )} ...... [a² - b²]

ㅤ➪ ( x - 5 ) ( x + 1 ) ( x - 1 )

•°• We got that , ( x - 1 ) is a factor of

ㅤㅤㅤㅤㅤㅤㅤㅤㅤ➪ㅤx³ - 5x² - x + 5

ㅤㅤㅤ꧁ ʙʀᴀɪɴʟʏ×ᴋɪᴋɪ ꧂

ㅤㅤㅤ

Answer 2

Answer:

hlo dude

Cells are the basic building blocks of all living things. ... Cells also contain the body's hereditary material and can make copies of themselves. Cells have many parts, each with a different function. Some of these parts, called organelles, are specialized structures that perform certain tasks within the cell.