Question

Show that
$( \sqrt{} 3 - \sqrt{} 5 ){}^{2}$
Is irrational. ​

Answer 1

Answer:

-2

Step-by-step explanation:

(√3 - √5) ^2

= (√3 x √3) - (√5 x √5 )

= 3 - 5

= - 2

Answer 2

Let (root3+root5!^2 be rational number

root3^2+2*root3*root5+root5^2=p/q

3+2root15+5=p/q

8+2root15=p/q

root15=p-8/2q.

here p,q,-8,2arerational numbers and we know that root15 is an irrational number.

(root3+root5)^2 is not a rational number..

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