Math, asked by ya852620, 1 month ago

Show that
 \sqrt{98}  +  \sqrt{8}  - 2 \sqrt{32}  =  \sqrt{2}



WITH EXPLANATION​

Answers

Answered by krishnarakshit365
0

  =  > \sqrt{98} + \sqrt{8} - 2 \sqrt{32} = \sqrt{2} \\  =  >  7\sqrt{2}  + 2 \sqrt{2}  - 8 \sqrt{2}  =  \sqrt{2} \\  =  > 9 \sqrt{2 }- 8 \sqrt{2}  =  \sqrt{2}  \\  =  >  \sqrt{2}  =  \sqrt{2}

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