Question

show that
${tan}^{4} a + {tan}^{2} a = {sec}^{4} a - {sec}^{2} a$
​

Answer 1

Step-by-step explanation:

=>tan⁴A +tan²A= sec⁴A-sec²a

=>tan²A(1+tan²A) = sec²A(sec²A-1)

=> tan²A.Sec²A = sec²A.tan²A

WE CAN SEE BOTH SIDES R EQUAL ...

HINT TO SOLVE::::___

U CAN SOLVE BOTH SIDE AND U WILL GET ANSWER ....

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