Question

Show that $x^3+y^3=(x+y)(x^2-xy+y^2)$ is an identity. (Hint: Use rational zeros theorem.)

Answer 1

Step-by-step explanation:

bhai ye tex ke karan kuch samaj me nahi aa raha hai

Answer 2

Answer:

true

Step-by-step explanation:

By rational zeros theorem, for x the possible zeros are ±y, ±y², ±y³.

Since x=-y works, we can verify one factor is x+y.

After we use synthetic division here, we can find out that

$x^3+y^3=(x+y)(x^2-xy+y^2)$