Math, asked by zarlishkhan9609, 11 months ago

show that the ΔABC is an isosceles triangle if the determinantΔ=[1111+cosA1+cosB1+cosCcos2A+cosAcos2B+cosBcos2C+cosC]=0

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Answered by basira79

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Abc is a triangle isoseles is 1111+cosA1

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