Question

Show that the acceleration due to gravity at the surface of moon is about 1/6 of that at the surface of the earth?​

Answer 1

Answer:

Given,

The new value of acceleration due to gravity, 

g′=100g×25=4g

g′=4g

We know that

The variation in the value of acceleration due to gravity is given by:

g′=(h+R)2gR2

4g=(h+R)2gR2

41=(h+R)2R2

Taking square root both side.

21=h+RR

h+R=2R

h=R