Show that the angle of an equilateral triangle are 60 digree each
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Hey !
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Angles of triangle=180 degrees
triangle A B C = 180 degrees
angle AB + Angle BC + Angle AC = 180 degrees
in equilateral triangle all sides are equal and hence all angles are equal. Hence AB=BC=AC
so 3AB=180 degrees
AB=180/3 degrees
so Angle AB = 60 degrees
Hence the proof
angle AB = Angle BC = Angle AC = 60 degrees
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#Hope it helps #
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______________
Angles of triangle=180 degrees
triangle A B C = 180 degrees
angle AB + Angle BC + Angle AC = 180 degrees
in equilateral triangle all sides are equal and hence all angles are equal. Hence AB=BC=AC
so 3AB=180 degrees
AB=180/3 degrees
so Angle AB = 60 degrees
Hence the proof
angle AB = Angle BC = Angle AC = 60 degrees
----------------------------
#Hope it helps #
--------------------------
Answered by
0
Hello mate ^_^
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Solution:
∆ABC is equilateral which means that
AB=BC=AC.
AB=AC means that ∠B=∠C (In triangle, angles opposite to equal sides are equal) .....(1)
AB=BC means that ∠A=∠C (In triangle, angles opposite to equal sides are equal) ...... (2)
From (1) and (2), we can say that
∠A=∠B=∠C .........(3)
Also, ∠A+∠B+∠C=180° (Angle sum property of triangle)
Putting (3) in the above equation, we get
∠A+∠A+∠A=180°
⇒3∠A=180°
⇒∠A=180/3=60° .......(4)
From (3) and (4), we can say that
∠A=∠B=∠C=60°
hope, this will help you.
Thank you______❤
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