show that the angle of an equilateral triangle are 60degree each
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Step-by-step explanation:
given:
ACB be an equilateral triangle
AB=BC=AC (all sides of equilateral triangle are equal)
to prove:
A=B=C=D=60
proof:
AB=AC
→ C = D (angles opposite to equal sides are equal) ......... (1)
AC=BC
→ B = A (angles opposite to equal sides are equal) ........ (2)
From (1)&(2)
A=B=C ...........(3)
In ∆ ABC,
A+B+C = 180 ( angle sum property of ∆le)
→A+A+A = 180 ( from 3)
→3 A = 180
→ A = 180/3
→ A = 60
A=B=C=60
hence proved
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