Math, asked by jatt13, 1 year ago

show that the angles contained


by the bisectors of two adjacent angles of a quadrilateral is equal to half the sum of the remaining angles

Answers

Answered by LOVVROY1
5
hello


yoir answer is



(i) AD = BC (opposite sides of a parallelogram are equal)

(ii) \(\angle\)DCB = \(\angle\)BAD (opposite angles are equal)

(iii) OC = OA (diagonals of a parallelogram bisect each other)

(iv) \(\angle\)DAB +\(\angle\)CDA = \(180^{\circ}\) (the sum of two adjacent angles of a parallelogram is \(180^{\circ}\) )

Similar questions