Show that the angles of an epuilateral triangle are 60° each
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Answer:
In ∆ABC,
AB = AC = BC.
∴ ∠A = ∠B = ∠C,
let this is x°.
But sum of three angles is 180°.
∠A +∠B +∠C=180°
x+x+x=180°
3x=180°
x=180°÷3
x=60°
∴ ∠A =60°
∠B = 60°
∠C =60°
Step-by-step explanation:
hope it will help you
Answered by
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Step-by-step explanation:
Given:
ΔABC is an equilateral triangle
To prove:-
∠A = ∠B = ∠C = 60°
Solution:-
AB = BC = AC (∵ ΔABC is an equilateral triangle)
Since, angles opposite to equal sides are equal
AB = BC
∴ ∠A = ∠C
BC = AC
∴ ∠A = ∠B
AB = AC
∴ ∠B = ∠C
∠A = ∠B = ∠C
By angle sum property of a triangle,
∠A + ∠B + ∠C = 180°
∠A + ∠A + ∠A = 180° (∵ ∠A = ∠B = ∠C)
3∠A = 180°
∠A = 180° ÷ 3
∠A = 60°
∴ ∠A = ∠B = ∠C = 60°
Hence proved
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