English, asked by keviwetozashumozashu, 5 months ago

show that the angles of an
equilateral triangle are 60degree each​

Answers

Answered by Mysterioushine
19

TO PROVE :-

  • The measure of each angle in an equilateral triangle is 60°

SOLUTION :-

\setlength{\unitlength}{1 cm}\begin{picture}(0,0)\thicklines\qbezier(0,0)(0,0)(2,2)\qbezier(0,0)(0,0)(4,0)\qbezier(2,2)(4,0)(4,0)\put(2.7,1.1){$\boldsymbol / $}\put(1.1,1.1){$\boldsymbol \backslash $}\put(1.8,2.1){$\bf A $}\put(-0.3,-0.3){$\bf B$}\put(4,-0.3){$\bf C$}\qbezier(3.6,0.4)(3.4,0.2)(3.6,0)\qbezier(0.4,0.4)(0.6,0.3)(0.4,0)\put(2,-0.1){$\boldsymbol |$}\qbezier(1.6,1.6)(1.8,1.3)(2.4,1.6) \put(4,1){\boxed{ \bold{@renuka1612}}}\end{picture}

Since the given triangle is equilateral . All sides are equal

 \implies \sf \: AB = AC = BC

The angles opposite to equal sides are also equal ,

 \implies \sf \angle A =  \angle B =  \angle C

Now ,

 \large {\underline  {\boxed {\sf{ \red{sum \: of \: all \: angles \: in \: a \: triangle \:  = 180 {}^{0} }}}}}

 \implies \sf \: \angle A  +  \angle B  +  \angle C  = 180 {}^{0}  \\  \\  \implies \sf \: 3(  \angle A ) = 180 {}^{0}  \\  \\  \implies \sf \:  \angle A =   \frac{180}{3}  \\  \\  \implies  {\underline {\boxed {\pink{\sf {\: \angle A =  60 {}^{0} }}}}}

 \implies  {\underline {\boxed {\blue{ \sf {\: \angle A =  \angle B =  \angle C  = 60 {}^{0} }}}}}

 \huge  {\underline{\blue{\boxed  {\green{\mathbf{HENCE\:PROVED}}}}}}

ADDITIONAL INFO :-

◉ Perimeter of an equilateral triangle = 3a

Where ,

  • a is side of the equilateral triangle

◉ Area of equilateral triangle is given by ,

 \large {\underline {\boxed {\sf{a =  \frac{ \sqrt{3}  }{4}  {a}^{2} }}}}

◉ If in a given triangle two sides are equal , then the triangle is said to be isosceles triangle

◉ If in a given triangle No sides are equal then the triangle is said to be scalene triangle

Answered by abdulrubfaheemi
0

TO PROVE :-

The measure of each angle in an equilateral triangle is 60°

SOLUTION :-

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Since the given triangle is equilateral . All sides are equal

\implies \sf \: AB = AC = BC⟹AB=AC=BC

The angles opposite to equal sides are also equal ,

\implies \sf \angle A = \angle B = \angle C⟹∠A=∠B=∠C

Now ,

\large {\underline {\boxed {\sf{ \red{sum \: of \: all \: angles \: in \: a \: triangle \: = 180 {}^{0} }}}}}

sumofallanglesinatriangle=180

0

\begin{gathered} \implies \sf \: \angle A + \angle B + \angle C = 180 {}^{0} \\ \\ \implies \sf \: 3( \angle A ) = 180 {}^{0} \\ \\ \implies \sf \: \angle A = \frac{180}{3} \\ \\ \implies {\underline {\boxed {\pink{\sf {\: \angle A = 60 {}^{0} }}}}}\end{gathered}

⟹∠A+∠B+∠C=180

0

⟹3(∠A)=180

0

⟹∠A=

3

180

∠A=60

0

\implies {\underline {\boxed {\blue{ \sf {\: \angle A = \angle B = \angle C = 60 {}^{0} }}}}}⟹

∠A=∠B=∠C=60

0

\huge {\underline{\blue{\boxed {\green{\mathbf{HENCE\:PROVED}}}}}}

HENCEPROVED

ADDITIONAL INFO :-

◉ Perimeter of an equilateral triangle = 3a

Where ,

a is side of the equilateral triangle

◉ Area of equilateral triangle is given by ,

\large {\underline {\boxed {\sf{a = \frac{ \sqrt{3} }{4} {a}^{2} }}}}

a=

4

3

a

2

◉ If in a given triangle two sides are equal , then the triangle is said to be isosceles triangle

◉ If in a given triangle No sides are equal then the triangle is said to be scalene triangle

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