show that the angles of an
equilateral triangle are 60degree each
Answers
TO PROVE :-
- The measure of each angle in an equilateral triangle is 60°
SOLUTION :-
Since the given triangle is equilateral . All sides are equal
The angles opposite to equal sides are also equal ,
Now ,
ADDITIONAL INFO :-
◉ Perimeter of an equilateral triangle = 3a
Where ,
- a is side of the equilateral triangle
◉ Area of equilateral triangle is given by ,
◉ If in a given triangle two sides are equal , then the triangle is said to be isosceles triangle
◉ If in a given triangle No sides are equal then the triangle is said to be scalene triangle
TO PROVE :-
The measure of each angle in an equilateral triangle is 60°
SOLUTION :-
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Since the given triangle is equilateral . All sides are equal
\implies \sf \: AB = AC = BC⟹AB=AC=BC
The angles opposite to equal sides are also equal ,
\implies \sf \angle A = \angle B = \angle C⟹∠A=∠B=∠C
Now ,
\large {\underline {\boxed {\sf{ \red{sum \: of \: all \: angles \: in \: a \: triangle \: = 180 {}^{0} }}}}}
sumofallanglesinatriangle=180
0
\begin{gathered} \implies \sf \: \angle A + \angle B + \angle C = 180 {}^{0} \\ \\ \implies \sf \: 3( \angle A ) = 180 {}^{0} \\ \\ \implies \sf \: \angle A = \frac{180}{3} \\ \\ \implies {\underline {\boxed {\pink{\sf {\: \angle A = 60 {}^{0} }}}}}\end{gathered}
⟹∠A+∠B+∠C=180
0
⟹3(∠A)=180
0
⟹∠A=
3
180
⟹
∠A=60
0
\implies {\underline {\boxed {\blue{ \sf {\: \angle A = \angle B = \angle C = 60 {}^{0} }}}}}⟹
∠A=∠B=∠C=60
0
\huge {\underline{\blue{\boxed {\green{\mathbf{HENCE\:PROVED}}}}}}
HENCEPROVED
ADDITIONAL INFO :-
◉ Perimeter of an equilateral triangle = 3a
Where ,
a is side of the equilateral triangle
◉ Area of equilateral triangle is given by ,
\large {\underline {\boxed {\sf{a = \frac{ \sqrt{3} }{4} {a}^{2} }}}}
a=
4
3
a
2
◉ If in a given triangle two sides are equal , then the triangle is said to be isosceles triangle
◉ If in a given triangle No sides are equal then the triangle is said to be scalene triangle