Question

show that the angles opposite to the equal sides in an isosceles traingle are equal.
*please answer as soon as possible*​

Answer 1

Answer:

Step-by-step explanation:

Let △ABC be an isosceles triangle such that AB =AC  Then we have to prove that ∠B=∠C Draw the bisector AD of ∠A meeting BC in D  

Now in triangles ABD and ACD We have AB=AC (Given)

∠BAD=∠CAD (because AD is bisector of ∠A

AD=AD   (Common side)

Therefore by SAS congruence condition we have  

△ABC≅△ACD

⇒∠B=∠C