Question

show that the bisector of angles of a parallelogram from a rectangle ​

Answer 1

HERES YOUR ANSWER

OA=OC

OB=OD (GIVEN)

so we have to prove that bisector of angles form a rectangle

In triangle AOB and COB

AO=CO

OB=OB

angle AOB= angle COB

AOB is congruent COB ....(by sss rule )

angle AOB+ angle COB= 180°

2 angle AOB= 180

angle AOB= 180/2

angle AOB = 90°

angle A= B=C=D=90°

SIMILARLY ABCD IS A RECTANGLE ....