show that the bisectors of a pair of interior angles made by two parllel lines are arllel to each other
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Given: AB and CD are two straight lines cut by a transversal EF at G and H respectively. GM and HN are the bisectors of corresponding angles ∠EGB and ∠GHD respectively such that GM∥HN.
To Prove: AB∥CD
Proof:
∵GM∥HN
∴∠1=∠2 (Corresponding angles)
⇒2∠1=2∠2⇒∠EGB=∠GHD⇒AB∥CD
(∠EGB & ∠GHD are corresponding angles formed by transversal EF with AB and CD and are equal.)
Hence, proved.
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