Math, asked by renumalik2608, 3 months ago


Show that the bisectors of angles of a parallelogram form a rectangle.​

Answers

Answered by shantanukumar9686
5

To prove: MNOP is a rectangle.

In parallelogram ABCD

∠A=∠D=90⁰

[they form a straight line]

∴IN△AMD,∠M=90⁰

∠M=∠N=90⁰

[they form a straight line]

Similarly,

∠M=∠P=90⁰

And

∠P=∠O=90⁰

∴∠MPO=∠PON∠ONM=∠NMO=90⁰

∴ MNOP is a rectangle. [A rectangle is a parallelogram with one angle 90⁰]

Answered by monicasuresh4
0

Answer:

ANSWER

To prove: MNOP is a rectangle.

In parallelogram ABCD

∠A=∠D=90

[they form a straight line]

∴IN△AMD,∠M=90

∠M=∠N=90

[they form a straight line]

Similarly,

∠M=∠P=90

And

∠P=∠O=90

∴∠MPO=∠PON∠ONM=∠NMO=90

∴ MNOP is a rectangle. [A rectangle is a parallelogram with one angle 90

]

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