Math, asked by joshipranav051, 1 day ago

show that the circle x square + y square=2 and x square + y square - 6 x minus 6 y + 10 = 0 touch each other do the circles touch externally or internally also find their point of contact

Answers

Answered by mandemroopa
1

The equation of circles are X2+y2-4x-6y-12=0 and X2+y2+6x+18y+26=0

centres are C1(2,3),C2(-3,-9)

R1=√4+9+12=5

R2=√9+81-26=8

C1,C2=√(2+3)2+(3+9)2

√25+144

13=r1+r2

Therefore, circles touch e externally.

Equation of common tangent is s1-s2=0

-10x-24y-38=0

5x+12y+19=0

The point of contact p divides C1,C2 in the ratio of 5:8

coordinates of p:(5(-3)+8.2\5+8,6(-9)+8.3/5+8)=1/13,-21/3

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