show that the cube of a positive integer is of the form 6q + r word Q is an integer and r is equal to 0 1 2 3 4 5
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Answer:Then, the positive integers are of the form 6q, 6q+1, 6q+2, 6q+3, 6q+4 and 6q+5. Hence, the cube of a positive integer of the form 6q + r, q is an integer and r = 0, 1, 2, 3, 4, 5 is also of the form 6m + r. Hope it helps.
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