Question

show that the cube of any positive integer is of the form 4m, 4m+1 ,4m + 3 for some integer m.

Answer 1

$\bold{Answer:-}$


$\bold{Step\: by \:step \:explanation}$



Using

$(a + b) {}^{3} = a {}^{3} + b {}^{3} + 3ab {}^{2} + 3a {}^{2} b$




⏩⏩Refer to the attachment above for your solution ⬆ ⬆






Hope it helps!

Answer 2

$\huge\bold\pink{Answer :-}$

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