Math, asked by gurmansaini993, 7 months ago

Show that the cube of any positive interger is of the form 4m or 4m+1 4m+3 where m is a whole number

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Answered by joshnajustin7a
3

Answer:

(4q + 3)3 = 64q3 + 144q2 + 108q + 27 = 4(16q3 + 36q2 + 27q + 6) + 3 = 4m + 3, where m is some integer. Hence, The cube of any positive integer is of the form 4m, 4m + 1 or 4m + 3 for some integer m.

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