Show that the diagnol of a rectangle are equal
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Answer:
Given:
A rectangle ABCD in which AC and BD are Diagonals.
To Prove:
Diagonals are equal i.e AC = BD
Proof: In ∆ABD & ∆BAC , we have
AB = BA { These sides are common in both triangles }
∠A = ∠B { Each side of a rectangle is of 90° }
AD = BC { Opposite Sides of a rectangle are equal to each other }
∴ ∆ABD ≅ ∆BAC ( By Side Angle Side SAS criteria )
Hence, BD = AC
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