Question

Show that the diagonal of a parallelogram divide it into four triangle of equal area.​

Answer 1

Answer:

According to the question,

Given: A parallelogram ABCD with diagonals AC & BD

Proof: ABCD is a parallelogram Diagonals of a parallelogram bisect each other

O is the mid-point of BD, i.e, OB=OD

& O is the mid-point of AC, i.e., OA=OC

In triangle ABC,

Since OA=OC From (2)

BO is the median of triangle ABC

implies ar (ΔAOB) = ar (ΔBOC)