Show that the diagonal of a parallogram divides into two congruent triangle
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given :a ||gm ABCD
& it's diagonal AC
to prove : diagonal AC divides ||gm into two∆'s
=>∆ADC is congruent to ∆ABC
proof :in ∆ADC and ∆ABC
AD=BC(opposite sides of parallelogram )
AB=CD(opposite sides of parallelogram)
AC=AC
therefore ,∆ ADC =~ ∆ABC
Hence proved ,that diagonal divide a ||gm into two congruent triangles.
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