Show that the diagonal of a triangle divides it into two triangles equal area
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Step-by-step explanation:
Show that the diagonal of a triangle divides it into two triangles equal areaGiven: A parallelogram ABCD.
Given: A parallelogram ABCD.
To prove: ar (ABC) = ar (CDA)
In ABC and ADC,
AB = CD (opposite sides of a parallelogram)
BC = DA (opposite sides of a parallelogram)
AC = CA (common)
ABC CDA (SSS)
Hence, ar (ABC) = ar (CDA) (congruent figures have equal areas)
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Answer:
here ABC is a triangle .
AD is its diagonal and it is dividing it into two parts
Step-by-step explanation:
please mark the answer as brainliest
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