show that the diagonals of a parallelogram divides it into four Triangles of equal area
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Let ABCD a // gm
and o is the centre
in ∆ AOB and ∆ COD
AO = CO diagonal bisect
BO = DO
angle aob = angle cod vertically opp. angle
so. ∆ aob =~ ∆ cod
as they are congruent they have same area
similarly proved others two ∆
hence proved
and o is the centre
in ∆ AOB and ∆ COD
AO = CO diagonal bisect
BO = DO
angle aob = angle cod vertically opp. angle
so. ∆ aob =~ ∆ cod
as they are congruent they have same area
similarly proved others two ∆
hence proved
mysticd:
plz , change the second line, O is the centre as diagonals bisect each other at O.
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