Question

show that the diagonals of a rhombus are ​

Answer 1

Answer:

Step-by-step explanation:

I think you not written complete question. But most probably, your question is "Show that the diagnols of a rhombus are perpendicular to each other"

So here is the answer----->

In triangle AOB and COB

AO = CO [because in a parallelogram the diagnols bisect each other]

OB = OB [Common side]

AB = CB [Rhombus sides are equal]

Thus triangle AOB is congruent to triangle COB

By CPCT angle AOB = angle COB

But we know that AOB + COB = 180 [Linear pair]

So both these angles are 90 degree

See attachment

Hope it helps!