Question

Show that the diagonals of a rhombus are perpendicular to each other.

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Answer 1

Answer:

Given: Rhombus ABCD To prove : AC BD Proof: Since ABCD is a rhombus AB = BC = CD = DA In AOB and COB, OA = OC OB = OB AB = CB AOB COB AOB = COB Since AC is a line, AOB + COB = 180 AOB + AOB = 180 2 AOB = 180 AOB = 180" " /2 = 90 From (1) COB = AOB COB = 90 Also, DOC = AOB = 90 AOD = COB = 90 Since DOC = AOB = AOD = COB ...

Answer 2

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Consider the rhombus as ABCD,

Let the center point be O

Now in triangle AOD and COD,

OA = OC ( Diagonals of IIgm bisect each other )

OD= OD (common )

AD = CD

Therefore, triangle AOD congruent triangle COD

Thus gives ,

Angle AOD = angle COD (cpct)

= 2 AOD = 180°

= AOD = 90°

So , the diagonals of a rhombus are perpendicular to each other.