show that the diagonals of a rhombus are perpendicular to each other..
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if rohmbus is given
let the rhombus be as ABCD
in which ab=bc=cd=da
OA=OC and OB=OF
now in ∆BOC AND DOC
OB=OD , BC=DC, OC=OC
∆BOC IS CONGRUENT TO DOC BY SSS
∆BOC =∆DOC ctct
∆BOC+ DOC=180 {LINEAR PAIR}
∆ BOC =DOC SIMILARLY
AOB=AOD =90
HENCE Proved that diagonals of a rohmbus are perpendicular to each other
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