Question

Show that the diagonals of a rhombus divide it into four congruent triangles

Answer 1

will just give an outline of how to prove it. You can write it up in a two-column proof. A rhombus is a parallelogram with four congruent sides. So, all sides of rhombus ABCD are congruent. That is AB ≅ BC ≅ CD ≅ AD We also know that the diagonals of a parallelogram bisect each other. Since a rhombus is a parallelogram, it also has this property. Therefore BE ≅ DE, AE ≅ CE. Therefore all 4 triangles are congruent by SSS. ..
hope it help's

Answer 2

Answer:

Heyaa..

Step-by-step explanation:

Refer to the attachment..