Show that the diagonals of a square are equal and bisect each other at right angles? ????
Answers
Answered by
27
∠OAD = ∠OCB ( transversal AC )
AD = CB ( opposite sides of a square)
(ii) In a Δ OAD and Δ OCB,
AC = BD ( by CPCT).
Δ ABC ≅ Δ BAD ( By SAS property)
∠ABC = ∠BAD ( = 90° )
BC = AD ( opppsite sides of a square)
AB = AB ( common line)
(i) In a Δ ABC and Δ BAD,
Proof:
To prove : AC = BD and AC and BD bisect each other at right angles.
Given that ABCD is a square.
AD = CB ( opposite sides of a square)
(ii) In a Δ OAD and Δ OCB,
AC = BD ( by CPCT).
Δ ABC ≅ Δ BAD ( By SAS property)
∠ABC = ∠BAD ( = 90° )
BC = AD ( opppsite sides of a square)
AB = AB ( common line)
(i) In a Δ ABC and Δ BAD,
Proof:
To prove : AC = BD and AC and BD bisect each other at right angles.
Given that ABCD is a square.
Answered by
0
Answer:
hope it helps
please mark me as brainliest
Attachments:
Similar questions