Question

show that the diagonals of a square are equal and bisect each other at right angle

Answer 1

$\pink{\:Hey\:mate\:your\:answer}$

GIVEN= ABCD IS A SQUARE.

To prove =] AC=BD AND AC BISECT BD.AC AND BD.

PROOF=] IN ∆ADB AND ∆BCA.

AD=BC(SIDES OF A SQUARE ARE EQUAL)

ANGLE BAD = ANGLE ABC ( 90° EACH)

AB = BA

∆ ADB CONGRUENT ∆BCA (SAS)

AC=BD (CPCT)

OD= OD (DIAGONAL BISECT)

AB=AD(SIDES ARE EQUAL)

AO= OA (COMMAN)

∆AOB~ ∆AOD(SSS)

ANGLE AOB= ANGLE AOD

ANGLE AOB + ANGLE = 180°( LINEAR PAIR)

ANGLE AOB=ANGLE AOD= 90°

AO BISECTS BD

AC BISCTS BD.

THANKS FOR YOUR QUESTION

Answer 2

see the attachment file............