Show that the diagonals of parralellogram divid it into four triangles of equal area.
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BO is the median in ΔABC
Area (ΔAOB) = Area (ΔBOC) equation.. (1)
In ΔBCD, CO is the median.
Ar(ΔBOC) = Ar(ΔCOD) equation..(2)
Therefore Ar(ΔCOD) = Ar(ΔAOD) equation.. (3)
From eq. (1), (2), and (3).
Ar(ΔAOB) = Ar(ΔBOC) = Ar(ΔCOD)=Ar(AOD)
Diagonals of a parallelogram divide it into four triangles of equal area.
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Area (ΔAOB) = Area (ΔBOC) equation.. (1)
In ΔBCD, CO is the median.
Ar(ΔBOC) = Ar(ΔCOD) equation..(2)
Therefore Ar(ΔCOD) = Ar(ΔAOD) equation.. (3)
From eq. (1), (2), and (3).
Ar(ΔAOB) = Ar(ΔBOC) = Ar(ΔCOD)=Ar(AOD)
Diagonals of a parallelogram divide it into four triangles of equal area.
**Hope this is helpful for u.**
*Please follow me.*
*Please mark as Brainliest answer.*
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