Show that the difference of any two sides of a triangle is less than the third side.
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Theorem which is, the sum of any two sides of a triangle must be greater than the third. Stated algebraically:
1. A < B + C ⇒ A - B < C (or) A - C < B
2. B < A + C ⇒ B - A < C (or) B - C < A
3. C < A + B ⇒ C - A < B (or) C - B < A
:)(: Hope This Helps !!!! :)(:
1. A < B + C ⇒ A - B < C (or) A - C < B
2. B < A + C ⇒ B - A < C (or) B - C < A
3. C < A + B ⇒ C - A < B (or) C - B < A
:)(: Hope This Helps !!!! :)(:
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