Question

Show that the dimension of U² and 2as are equivalent

Answer 1

Answer:

V=u+at

S=ut+1\2at2

Now the derivation:

From the first equation we have :

at=v−u

t=v−u\a

Now putting the value of t in the second equation of motion:

s=u(v−u\a)+1\2a(v−u\a)2

s=uv−u2\a+a(v2+u2–2vu)\2a2

s=uv−u2\a+(v2+u2+2vu)\2a

s=(2uv−2u2+v2+u2–2vu)\2a

2as=v2−u2

v2=u2+2as